-0.3x^2+x-(n/5)

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Solution for -0.3x^2+x-(n/5) equation:


x in (-oo:+oo)

x-(n/5)-0.3*x^2 = 0

x-1/5*n-0.3*x^2 = 0

DELTA = 1^2-(-0.3*(-1/5)*4*n)

DELTA = 1-0.24*n

1-0.24*n = 0

1-0.24*n = 0 // - 1

-0.24*n = -1 // : -0.24

n = -1/(-0.24)

n = 4.16666667

DELTA = 0 <=> t_1 = 4.16666667

x = -1/(-0.3*2) i n = 4.16666667

x = 1.66666667 i n = 4.16666667

( x = ((1-0.24*n)^(1/2)-1)/(-0.3*2) or x = (-(1-0.24*n)^(1/2)-1)/(-0.3*2) ) i n > 4.16666667

( x = -1.66666667*((1-0.24*n)^(1/2)-1) or x = 1.66666667*((1-0.24*n)^(1/2)+1) ) i n > 4.16666667

n-4.16666667 > 0

n-4.16666667 > 0 // + 4.16666667

n > 4.16666667

x in { 1.66666667, -1.66666667*((1-0.24*n)^(1/2)-1), 1.66666667*((1-0.24*n)^(1/2)+1) }

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